Why composites? Put the material where it matters.
Stiff fibers carry load. A surrounding matrix holds them together and transfers load between them. Changing the ingredients and their arrangement gives engineers another way to design.
From a real object to an engineering question
See it. Question it. Model a small part of it.
From aircraft to bicycles, composites help designers balance stiffness and mass. The exercises do not reproduce a manufacturer’s proprietary design or certify its performance. No manufacturer endorsement is implied.
Melvin Loi · CC BY-SA 2.0. Display cropped; image adaptations share the same license. Photo source · License
Sport · a carbon bicycle frame
Carbon fibers, resin and layer placement let bicycle designers tailor composite parts. Trek describes this construction for frames, wheels and handlebars; the pictured frame is Edelsten, not Trek. Manufacturer background ↗
Ask: How does changing ply direction change the response to different loads?
Pick any block to jump back and forth. Your design stays with you. Try one change, see what happens, then choose your next move.
Your challenge: make a 120 × 25 mm strip—about the length of a small ruler. Hold one end still and push down on the other with 0.5 N (about the weight of 50 g). Can you keep the bend below 2 mm and the strip’s mass below 7 g? The strip’s length, width and push stay the same.
Current design: Glass fiber / resin · 60% fiber → 8 plies · 1.00 mm → bending study. Changes upstream automatically update the later stages.
Part 1 · Micro
Mix your material.
Start with glass fibers held together by resin. One thin layer of this mixture is called a lamina. A stack of bonded layers is a laminate.
Resin: 40% · Voids: 0%
Stiffness along the fibers45.2 GPa
Density · mass for the same volume2010 kg/m³
A bigger stiffness number means the material stretches less under the same pull. Lower density means an equal-sized piece has less mass.
How much stiffness for its mass?
This score compares stiffness with density. Higher means more stiffness for the same mass in a straight bar pulled along its length.
Glass fiber / resin
22.5
Aluminum
25.9
At equal axial stiffness and length, this ideal composite bar needs 115% of the aluminum bar’s mass, if its cross-sectional area can change freely.
This is not a wing, bicycle or aircraft prediction. Strength, buckling, joints and minimum thickness may govern a real design.
∑ Equations, teaching values and assumptions
Axial modulus = fiber fraction × fiber modulus + resin fraction × resin modulus. Density follows the same volume-weighted rule. Specific modulus = modulus ÷ density.
For a bar, axial stiffness = EA/L. At equal length and axial stiffness, mass ratio = (composite density / composite modulus) ÷ (metal density / metal modulus).
Perfect bonding, aligned continuous fibers, uniform strain, linear elasticity, no voids and room-temperature behavior. This rule does not predict transverse stiffness, failure, fatigue or process effects. More fiber is not automatically manufacturable or better.
Website teaching study only. Workbench links open the existing exercises; they do not transfer or save this trial into the master database. This page’s trials reset when you reload.
The website builds intuition. Workbench is where you choose traceable material records, define geometry and loads, run the full available models and examine their limits. These links use the existing shared curriculum—not a separate set of exercise databases.